sethosterloh
sethosterloh
04-08-2015
Mathematics
contestada
4y=3/x^2+2, what is the value of x?
Respuesta :
gogochushij
gogochushij
04-08-2015
[tex]4y=\frac{3}{x^2}+2[/tex] (1/equation)
[tex]\frac{1}{4y}=\frac{1}{\frac{3}{x^2}}+\frac{1}{2}[/tex]
[tex]\frac{1}{4y}=\frac{x^2}{3}+\frac{1}{2}[/tex] (*3)
[tex] \frac{3}{4y}=\frac{3x^2}{3}+\frac{3}{2}[/tex]
[tex]\frac{3}{4y}=x^2+\frac{3}{2}[/tex]
[tex]\frac{3}{4y}-\frac{3}{2}=x^2[/tex]
[tex]x^2=\frac{3}{4y}-\frac{3}{2}[/tex]
[tex]\sqrt{x^2}=\sqrt{\frac{3}{4y}-\frac{3}{2}}[/tex]
[tex]|x|= \sqrt{\frac{3}{4y}-\frac{3}{2}} [/tex]
[tex]x=\pm\sqrt{\frac{3}{4y}-\frac{3}{2}[/tex]
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